The nine will play the last game of the series with Brown on Holmes Field at 3.30 o'clock this afternoon.
Brown won the first game, 9-7, largely through Harvard's errors; but Harvard won the next two games, the score being 6-1 both times. No arrangements have been made to play off the tie in case Brown wins this afternoon.
The batting order of the teams will be as follows:
HARVARD. BROWN.
Dean, 2b. s. s., Phillips.
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Scannell, c. 2b., Fultz.
Burgess, r. f. r. f., Robinson.
Clarkson, c. f. 3b., Lauder.
Haughton, 1b. p., Brady.
Rand, l. f. 1b., Rodman.
Stevenson, 3b. l. f., Gammons.
Paine, p. c., Dunne.
Chandler, s. s. c. f., Sedgewick.
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